diff --git a/wrap/python/spot.py b/wrap/python/spot.py
index dc91a0a08..fcfc1e3cc 100644
--- a/wrap/python/spot.py
+++ b/wrap/python/spot.py
@@ -706,6 +706,6 @@ for fun in dir(formula):
                                              fun[:4] == 'has_')):
         _addfilter(fun)
 
-for fun in ['remove_x', 'get_literal', 'relabel', 'relabel_bse',
-            'simplify', 'unabbreviate_ltl']:
+for fun in ['remove_x', 'relabel', 'relabel_bse',
+            'simplify', 'unabbreviate']:
     _addmap(fun)
diff --git a/wrap/python/tests/randltl.ipynb b/wrap/python/tests/randltl.ipynb
index fd163cbce..dca0ebc00 100644
--- a/wrap/python/tests/randltl.ipynb
+++ b/wrap/python/tests/randltl.ipynb
@@ -17,7 +17,8 @@
    "pygments_lexer": "ipython3",
    "version": "3.4.3+"
   },
-  "name": ""
+  "name": "",
+  "signature": "sha256:b69bb80f870979f9654dbf2c1bcc0f26f652956e1f1ea4189d5c8078caa067c6"
  },
  "nbformat": 3,
  "nbformat_minor": 0,
@@ -601,8 +602,7 @@
      "cell_type": "markdown",
      "metadata": {},
      "source": [
-      "You may have noticed that the return type of randltl is 'formulaiterator'.<br/>\n",
-      "Since the boolean functions and the 'mapping' functions return an iterator of the same type, this means these operations can be chained like this:"
+      "Since the boolean filters and mapping functions return an iterator of the same type, these operations can be chained like this:"
      ]
     },
     {
@@ -632,6 +632,43 @@
       }
      ],
      "prompt_number": 15
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "for formula in spot.randltl(3, 10).simplify().unabbreviate(\"WMGFR\"): print(formula)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "0\n",
+        "!(1 U !p1)\n",
+        "1 U ((p0 U ((p0 & p1) | (p1 R p0))) | !(1 U !((1 U !p1) & (1 U p1))))\n",
+        "1 U (!p2 U ((p0 & !p2) | (p0 R !p2)))\n",
+        "(!p1 U (((1 U !(1 U !p1)) R !p1) | (!p1 & (1 U !(1 U !p1))))) | !(1 U !(p0 | (1 U p1)))\n",
+        "X(p2 & X(p2 U (!p0 | (p2 W !p0))))\n",
+        "(1 U p2) | (X(!p2 | !(1 U !p2)) U ((1 U p2) U (!p1 & (1 U p2))))\n",
+        "XX!(1 U !((X!p1 U (!p2 U (!p0 & !p2))) | X!(1 U !p0)))\n",
+        "XX(1 U (p1 U ((p0 & p1) | (p0 R p1))))\n",
+        "p2 & Xp0\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [],
+     "language": "python",
+     "metadata": {},
+     "outputs": [],
+     "prompt_number": 16
     }
    ],
    "metadata": {}