{ "metadata": { "name": "", "signature": "sha256:e975b9a64657f38248c434a89f29b28f0bf90f9c40b7e8afdd7459734cbdcd38" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "code", "collapsed": false, "input": [ "import spot\n", "spot.setup()" ], "language": "python", "metadata": {}, "outputs": [], "prompt_number": 1 }, { "cell_type": "markdown", "metadata": {}, "source": [ "Let's build a small automaton to use as example." ] }, { "cell_type": "code", "collapsed": false, "input": [ "aut = spot.translate('G(Fa <-> Xb)'); aut" ], "language": "python", "metadata": {}, "outputs": [ { "metadata": {}, "output_type": "pyout", "prompt_number": 2, "svg": [ "\n", "\n", "\n", "\n", "\n", "\n", "G\n", "\n", "\n", "\n", "0\n", "\n", "0\n", "\n", "\n", "I->0\n", "\n", "\n", "\n", "\n", "1\n", "\n", "1\n", "\n", "\n", "0->1\n", "\n", "\n", "!a\n", "\n", "\n", "2\n", "\n", "2\n", "\n", "\n", "0->2\n", "\n", "\n", "a\n", "\n", "\n", "3\n", "\n", "3\n", "\n", "\n", "0->3\n", "\n", "\n", "!a\n", "\n", "\n", "1->1\n", "\n", "\n", "!a & b\n", "\n", "\n", "1->2\n", "\n", "\n", "a & b\n", "\u24ff\n", "\n", "\n", "2->1\n", "\n", "\n", "!a & b\n", "\n", "\n", "2->2\n", "\n", "\n", "a & b\n", "\u24ff\n", "\n", "\n", "2->3\n", "\n", "\n", "!a & b\n", "\n", "\n", "3->3\n", "\n", "\n", "!a & !b\n", "\u24ff\n", "\n", "\n", "\n" ], "text": [ " *' at 0x7f4f0c2e0810> >" ] } ], "prompt_number": 2 }, { "cell_type": "markdown", "metadata": {}, "source": [ "The call to `couvreur99()` just instanciate the emptiness check, but does not run the check. Calling `check()` will return `None` if no accepting run was found. Otherwise the presence of the accepting run is established, but an accepting run hasn't necessarily been calculated: calling `accepting_run()` on the result will cause this computation to happen.\n", "\n", "\n", "In the example below, we do not check the result of `check()` because we know that the input formula is satisfiable, so the automaton has an accepting run." ] }, { "cell_type": "code", "collapsed": false, "input": [ "run = spot.couvreur99(aut).check().accepting_run(); run" ], "language": "python", "metadata": {}, "outputs": [ { "metadata": {}, "output_type": "pyout", "prompt_number": 3, "text": [ "Prefix:\n", " 0\n", " | !a\n", "Cycle:\n", " 1\n", " | a & b\t{0}\n", " 2\n", " | !a & b" ] } ], "prompt_number": 3 }, { "cell_type": "markdown", "metadata": {}, "source": [ "Accessing the contents of the run can be done via the `prefix` and `cycle` lists." ] }, { "cell_type": "code", "collapsed": false, "input": [ "print(spot.bdd_format_formula(aut.get_dict(), run.prefix[0].label))\n", "print(run.cycle[0].acc)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "!a\n", "{0}\n" ] } ], "prompt_number": 4 }, { "cell_type": "markdown", "metadata": {}, "source": [ "To convert the run into a word, using `spot.twa_word()`. Note that our runs are labeled by Boolean formulas that are not necessarily a conjunction of all involved litterals. The word is just the projection of the run on its labels." ] }, { "cell_type": "code", "collapsed": false, "input": [ "word = spot.twa_word(run); word" ], "language": "python", "metadata": {}, "outputs": [ { "metadata": {}, "output_type": "pyout", "prompt_number": 5, "text": [ "!a; cycle{a & b; !a & b}" ] } ], "prompt_number": 5 }, { "cell_type": "markdown", "metadata": {}, "source": [ "Accessing the different formulas (stored as BDDs) can be done again via the `prefix` and `cycle` lists." ] }, { "cell_type": "code", "collapsed": false, "input": [ "print(spot.bdd_format_formula(aut.get_dict(), word.prefix[0]))\n", "print(spot.bdd_format_formula(aut.get_dict(), word.cycle[0]))\n", "print(spot.bdd_format_formula(aut.get_dict(), word.cycle[1]))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "!a\n", "a & b\n", "!a & b\n" ] } ], "prompt_number": 6 }, { "cell_type": "markdown", "metadata": {}, "source": [ "Calling `simplifify()` will produce a shorter word that is compatible with the original word. For instance in the above word, the initial `!a` is compatible with both `a & b` and `!a & b`. The word obtained by restricting `!a` to `!a & b` is therefore still accepted, but it allows removing the prefix by rotating the cycle:" ] }, { "cell_type": "code", "collapsed": false, "input": [ "word.simplify()\n", "word" ], "language": "python", "metadata": {}, "outputs": [ { "metadata": {}, "output_type": "pyout", "prompt_number": 7, "text": [ "cycle{!a & b; a & b}" ] } ], "prompt_number": 7 } ], "metadata": {} } ] }