python: add bindings for bdd_to_formula()
Follow-up to an email from Ayrat Khalimov. * python/spot/impl.i: Include twa/formula2bdd.hh. * python/spot/__init__.py: Make the dictionnary optional. * spot/twa/formula2bdd.cc: Throw an exception instead of asserting. * tests/python/bdditer.py: New file. * tests/Makefile.am: Add it. * NEWS: Update.
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tests/python/bdditer.py
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tests/python/bdditer.py
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# -*- mode: python; coding: utf-8 -*-
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# Copyright (C) 2017 Laboratoire de Recherche et Développement de l'Epita
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# (LRDE).
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#
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# This file is part of Spot, a model checking library.
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#
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# Spot is free software; you can redistribute it and/or modify it
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# under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# Spot is distributed in the hope that it will be useful, but WITHOUT
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# ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
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# or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public
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# License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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# Tests different ways to explore a BDD label, as discussed in
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# http://lists.lrde.epita.fr/pipermail/spot/2017q1/000117.html
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import spot
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import buddy
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import sys
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run = spot.translate('a & !b').accepting_run()
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b = run.prefix[0].label
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c = buddy.bdd_satone(b)
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assert c != buddy.bddfalse
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res = []
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while c != buddy.bddtrue:
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var = buddy.bdd_var(c)
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h = buddy.bdd_high(c)
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if h == buddy.bddfalse:
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res.append(-var)
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c = buddy.bdd_low(c)
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else:
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res.append(var)
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c = h
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assert res == [0, -1]
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res2 = []
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for i in run.aut.ap():
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res2.append((i, run.aut.register_ap(i)))
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assert str(res2) == '[(a, 0), (b, 1)]'
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f = spot.bdd_to_formula(b)
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assert f._is(spot.op_And)
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assert f[0]._is(spot.op_ap)
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assert f[1]._is(spot.op_Not)
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assert f[1][0]._is(spot.op_ap)
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assert str(f) == 'a & !b'
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try:
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f = spot.bdd_to_formula(b, spot.make_bdd_dict())
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sys.exit(2)
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except RuntimeError as e:
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assert "not in the dictionary" in str(e)
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