formula: rename the constants for consistency
False/True are problematic in Python, and I don't like that the enum is op::False but the constructor formula::ff(). So let's just use ff and tt everywhere, and also eword instead of EmptyWord. * src/ltlast/formula.hh (False, True, EmptyWord, AP, is_false, is_true): Rename to... (ff, tt, eword, ap, is_ff, is_tt): ... these. * iface/ltsmin/ltsmin.cc, src/ltlast/formula.cc, src/ltlvisit/apcollect.cc, src/ltlvisit/dot.cc, src/ltlvisit/mark.cc, src/ltlvisit/mutation.cc, src/ltlvisit/print.cc, src/ltlvisit/relabel.cc, src/ltlvisit/simpfg.cc, src/ltlvisit/simplify.cc, src/ltlvisit/snf.cc, src/ltlvisit/unabbrev.cc, src/twa/acc.cc, src/twa/acc.hh, src/twa/formula2bdd.cc, src/twaalgos/gtec/gtec.cc, src/twaalgos/hoa.cc, src/twaalgos/ltl2taa.cc, src/twaalgos/ltl2tgba_fm.cc, src/twaalgos/neverclaim.cc, src/twaalgos/product.cc, src/twaalgos/remfin.cc, src/twaalgos/safety.cc, src/tests/parseerr.test, src/tests/utf8.test, wrap/python/spot.py: Adjust.
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27 changed files with 211 additions and 211 deletions
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@ -60,9 +60,9 @@ namespace spot
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return src;
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op o = f.kind();
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std::string str = (o == op::AP) ? f.ap_name() : f.kindstr();
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std::string str = (o == op::ap) ? f.ap_name() : f.kindstr();
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if (o == op::AP || f.is_constant())
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if (o == op::ap || f.is_constant())
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*sinks_ << " " << src << " [label=\""
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<< str << "\", shape=box];\n";
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else
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@ -71,10 +71,10 @@ namespace spot
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int childnum = 0;
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switch (o)
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{
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case op::False:
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case op::True:
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case op::EmptyWord:
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case op::AP:
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case op::ff:
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case op::tt:
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case op::eword:
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case op::ap:
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case op::Not:
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case op::X:
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case op::F:
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