python: improve kripke_graph bindings
Related to issue #376. * spot/kripke/kripkegraph.hh: Avoid indirect type definitions for the benefit of Swig. * python/spot/impl.i: Add bindings for iterators over kripke_graph states and edges. * tests/python/kripke.py: New file. * tests/Makefile.am: Add it. * NEWS: Update.
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tests/python/kripke.py
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tests/python/kripke.py
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# -*- mode: python; coding: utf-8 -*-
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# Copyright (C) 2019 Laboratoire de Recherche et Développement de l'Epita
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# (LRDE).
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#
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# This file is part of Spot, a model checking library.
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#
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# Spot is free software; you can redistribute it and/or modify it
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# under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# Spot is distributed in the hope that it will be useful, but WITHOUT
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# ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
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# or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public
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# License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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import spot
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import buddy
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bdict = spot.make_bdd_dict()
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k = spot.make_kripke_graph(bdict)
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p1 = buddy.bdd_ithvar(k.register_ap("p1"))
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p2 = buddy.bdd_ithvar(k.register_ap("p2"))
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cond1 = p1 & p2
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cond2 = p1 & -p2
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cond3 = -p1 & -p2
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s2 = k.new_state(cond1)
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s1 = k.new_state(cond2)
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s3 = k.new_state(cond3)
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k.new_edge(s1, s2)
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k.new_edge(s2, s2)
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k.new_edge(s1, s3)
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k.new_edge(s3, s3)
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k.new_edge(s3, s2)
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k.set_init_state(s1)
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hoa="""HOA: v1
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States: 3
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Start: 0
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AP: 2 "p1" "p2"
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acc-name: all
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Acceptance: 0 t
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properties: state-labels explicit-labels state-acc
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--BODY--
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State: [0&!1] 0 "1"
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1 2
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State: [0&1] 1 "0"
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1
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State: [!0&!1] 2 "2"
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2 1
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--END--"""
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assert hoa == k.to_str('HOA')
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assert k.num_states() == 3
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assert k.num_edges() == 5
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res = []
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for e in k.out(s1):
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res.append((e.src, e.dst))
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assert res == [(1, 0), (1, 2)]
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res = []
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for e in k.edges():
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res.append((e.src, e.dst))
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assert res == [(1, 0), (0, 0), (1, 2), (2, 2), (2, 0)]
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res = []
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for s in k.states():
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res.append(s.cond())
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assert res == [cond1, cond2, cond3]
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assert k.states()[0].cond() == cond1
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assert k.states()[1].cond() == cond2
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assert k.states()[2].cond() == cond3
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