* buddy/src/bdd.h, buddy/src/bvec.h, buddy/src/fdd.h: Rename as... * buddy/src/bddx.h, buddy/src/bvecx.h, buddy/src/fddx.h: ... these. * buddy/src/Makefile.am: Build libbddx.la instead of libbdd.la. * buddy/examples/Makefile.def: Use it. * Makefile.am, buddy/src/bddtest.cxx, buddy/src/bvec.c, buddy/src/cppext.cxx, buddy/src/fdd.c, buddy/src/imatrix.h, buddy/src/kernel.h, buddy/examples/adder/adder.cxx, buddy/examples/bddcalc/parser_.h, buddy/examples/bddtest/bddtest.cxx, buddy/examples/cmilner/cmilner.c, buddy/examples/fdd/fdd.cxx, buddy/examples/milner/milner.cxx, buddy/examples/money/money.cxx, buddy/examples/queen/queen.cxx, buddy/examples/solitare/solitare.cxx, m4/buddy.m4, src/ltlvisit/apcollect.hh, src/ltlvisit/simplify.hh, src/misc/bddlt.hh, src/misc/bddop.hh, src/misc/minato.hh, src/priv/acccompl.hh, src/priv/accconv.hh, src/priv/accmap.hh, src/priv/bddalloc.cc, src/tgba/bdddict.hh, src/tgba/bddprint.hh, src/tgba/tgbamask.hh, src/tgba/tgbasafracomplement.cc, src/tgbaalgos/emptiness.hh, src/tgbaalgos/gtec/sccstack.hh, src/tgbaalgos/neverclaim.cc, src/tgbaalgos/powerset.cc, src/tgbaalgos/sccfilter.hh, src/tgbaalgos/sccinfo.hh, src/tgbaalgos/weight.hh, wrap/python/buddy.i: Adjust. * NEWS, README: Document it.
76 lines
2.3 KiB
C++
76 lines
2.3 KiB
C++
#include "bvecx.h"
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#include <iostream>
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using namespace std;
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/* Find a solution to the send-more-money example
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* The problem is to assign values for the digits s,e,n,d,m,o,r,y
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* in such a way that the following equation is true:
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*
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* s e n d +
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* m o r e =
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* m o n e y
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*
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* with the additional constraints that all digits must have different values
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* and s>0 and m>0.
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*/
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int main(void)
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{
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using namespace std ;
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// Allocate 11 domains with room for up to 3*10
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static int dom[11] = {30,30,30,30,30,30,30,30,30,30,30};
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bdd_init(10000,10000);
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fdd_extdomain(dom,11);
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// Assign binary vectors (expressions) to the digits
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bvec s = bvec_varfdd(0); // The 's' digit
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bvec e = bvec_varfdd(1); // The 'e' digit
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bvec n = bvec_varfdd(2); // ...
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bvec d = bvec_varfdd(3);
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bvec m = bvec_varfdd(4);
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bvec o = bvec_varfdd(5);
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bvec r = bvec_varfdd(6);
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bvec y = bvec_varfdd(7);
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bvec m1 = bvec_varfdd(8); // Carry out 1
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bvec m2 = bvec_varfdd(9); // Carry out 2
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bvec m3 = bvec_varfdd(10); // Carry out 3
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// Create a few constants of the right bit number (5)
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bvec c10 = bvec_con(5,10);
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bvec c2 = bvec_con(5,2);
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bvec c0 = bvec_con(5,0);
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// Create constraints
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// Constraint 1: addition of the last digits and constraints on
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// the max. value of the involved variables and carry-out
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bdd t1 = (d + e == y + m1*10) & d<c10 & e<c10 & y<c10 & m1<c2;
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// The use of "m1*10" instead of "m1*c10" avoids a bitnum mismatch since
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// "m1*10" results in 5 bits but "m1*c10" results in 10 bits!
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// And so on ...
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bdd t2 = (n + r + m1 == e + m2*10) & n<c10 & r<c10 & m2<c2;
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bdd t3 = (e + o + m2 == n + m3*10) & o<c10 & m3<c2;
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bdd t4 = (s + m + m3 == o + m*10) & s<c10 & m<c2;
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bdd t5 = (m > c0 & s > c0);
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// Make sure all digits are different
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bdd t6 = (s!=e & s!=n & s!=d & s!=m & s!=o & s!=r & s!=y);
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bdd t7 = (e!=n & e!=d & e!=m & e!=o & e!=r & e!=y);
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bdd t8 = (n!=d & n!=m & n!=o & n!=r & n!=y);
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bdd t9 = (d!=m & d!=o & d!=r & d!=y);
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bdd t10 = (m!=o & m!=r & m!=y);
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bdd t11 = (o!=r & o!=y);
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bdd t12 = (r!=y);
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// Join all constraints
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bdd t = t1 & t2 & t3 & t4 & t5 & t6 & t7 & t8 & t9 & t10 & t11 & t12;
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// Print result
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cout << fddset << t << endl;
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return 0;
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}
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