b5d688dc97
Fixes #401, reported by Victor Khomenko. * spot/twaalgos/stutter.cc (sl, sl2): If {} is accepting, upgrade the acceptance condition. * tests/core/stutter-tgba.test, tests/python/stutter.py: Add test cases.
62 lines
2.2 KiB
Python
62 lines
2.2 KiB
Python
# -*- mode: python; coding: utf-8 -*-
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# Copyright (C) 2019, 2020 Laboratoire de Recherche et Développement de
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# l'Epita (LRDE).
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#
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# This file is part of Spot, a model checking library.
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#
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# Spot is free software; you can redistribute it and/or modify it
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# under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# Spot is distributed in the hope that it will be useful, but WITHOUT
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# ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
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# or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public
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# License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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# Test that the spot.gen package works, in particular, we want
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# to make sure that the objects created from spot.gen methods
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# are usable with methods from the spot package.
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import spot
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def explain_stut(f):
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f = spot.formula(f)
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pos = spot.translate(f)
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neg = spot.translate(spot.formula.Not(f))
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word = spot.product(spot.closure(pos), spot.closure(neg)).accepting_word()
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if word is None:
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print(f, "is stutter invariant")
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return
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word.simplify()
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# This line used to be missing, causing issue #388.
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word.use_all_aps(pos.ap_vars())
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waut = word.as_automaton()
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aut = neg if waut.intersects(pos) else pos
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word2 = spot.sl2(waut).intersecting_word(aut)
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word2.simplify()
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return(word, word2)
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# Test from issue #388
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w1, w2 = explain_stut('{(a:b) | (a;b)}|->Gc')
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assert str(w1) == 'a & !b & !c; cycle{!a & b & !c}'
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assert str(w2) == 'a & !b & !c; a & !b & !c; cycle{!a & b & !c}'
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# Test from issue #401
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w1, w2 = explain_stut('G({x} |-> ({x[+]} <>-> ({Y1[+]} <>=> Y2)))')
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assert str(w1) == 'cycle{!Y1 & !Y2 & x; Y1 & Y2 & x}'
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assert str(w2) == 'cycle{!Y1 & !Y2 & x; Y1 & Y2 & x; Y1 & Y2 & x}'
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# Related to issue #401 as well. sl() and sl2() should upgrade
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# the t acceptance condition into inf(0).
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pos = spot.translate('Xa & XXb')
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w = pos.accepting_word().as_automaton()
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assert w.acc().is_t()
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assert not spot.sl2(w).acc().is_buchi()
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assert not spot.sl(w).acc().is_buchi()
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