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python: update the formulaiterator bindings

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* wrap/python/spot.py: Add the unabbreviate() method, and
remove unabbrivate_ltl() and get_literal().
* wrap/python/tests/randltl.ipynb: Demonstrate unabbreviate().
This commit is contained in:
Alexandre Duret-Lutz 2015-10-18 11:54:51 +02:00
parent 1d30242d17
commit 9689c4ccfc
2 changed files with 42 additions and 5 deletions
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4
wrap/python/spot.py
View file

@ -706,6 +706,6 @@ for fun in dir(formula):
fun[:4] == 'has_')):
_addfilter(fun)
for fun in ['remove_x', 'get_literal', 'relabel', 'relabel_bse',
'simplify', 'unabbreviate_ltl']:
for fun in ['remove_x', 'relabel', 'relabel_bse',
'simplify', 'unabbreviate']:
_addmap(fun)

43
wrap/python/tests/randltl.ipynb
View file

@ -17,7 +17,8 @@
"pygments_lexer": "ipython3",
"version": "3.4.3+"
},
"name": ""
"name": "",
"signature": "sha256:b69bb80f870979f9654dbf2c1bcc0f26f652956e1f1ea4189d5c8078caa067c6"
},
"nbformat": 3,
"nbformat_minor": 0,
@ -601,8 +602,7 @@
"cell_type": "markdown",
"metadata": {},
"source": [
"You may have noticed that the return type of randltl is 'formulaiterator'.<br/>\n",
"Since the boolean functions and the 'mapping' functions return an iterator of the same type, this means these operations can be chained like this:"
"Since the boolean filters and mapping functions return an iterator of the same type, these operations can be chained like this:"
]
},
{
@ -632,6 +632,43 @@
}
],
"prompt_number": 15
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"for formula in spot.randltl(3, 10).simplify().unabbreviate(\"WMGFR\"): print(formula)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"0\n",
"!(1 U !p1)\n",
"1 U ((p0 U ((p0 & p1) | (p1 R p0))) | !(1 U !((1 U !p1) & (1 U p1))))\n",
"1 U (!p2 U ((p0 & !p2) | (p0 R !p2)))\n",
"(!p1 U (((1 U !(1 U !p1)) R !p1) | (!p1 & (1 U !(1 U !p1))))) | !(1 U !(p0 | (1 U p1)))\n",
"X(p2 & X(p2 U (!p0 | (p2 W !p0))))\n",
"(1 U p2) | (X(!p2 | !(1 U !p2)) U ((1 U p2) U (!p1 & (1 U p2))))\n",
"XX!(1 U !((X!p1 U (!p2 U (!p0 & !p2))) | X!(1 U !p0)))\n",
"XX(1 U (p1 U ((p0 & p1) | (p0 R p1))))\n",
"p2 & Xp0\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": [],
"prompt_number": 16
}
],
"metadata": {}